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class Solution {
    fun isAnagram(s: String, t: String): Boolean {
        if(s.length != t.length) return false

        val count = mutableMapOf<Char, Int>()

        for(char in s) {
            if(count[char] == null) count[char] = 1
            else count[char] = count[char]!! + 1
        }
        
        for(char in t) {
            val v = (count[char] ?: return false) - 1
            if(v == 0) count.remove(char)
            if(v > 0) count[char] = v;
        }

        return count.isEmpty()
    }
}